(9y^2-24)/(3y^2-12y)

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Solution for (9y^2-24)/(3y^2-12y) equation: 


D( y )

3*y^2-(12*y) = 0

3*y^2-(12*y) = 0

3*y^2-(12*y) = 0

3*y^2-12*y = 0

3*y^2-12*y = 0

DELTA = (-12)^2-(0*3*4)

DELTA = 144

DELTA > 0

y = (144^(1/2)+12)/(2*3) or y = (12-144^(1/2))/(2*3)

y = 4 or y = 0

y in (-oo:0) U (0:4) U (4:+oo)

(9*y^2-24)/(3*y^2-(12*y)) = 0

(9*y^2-24)/(3*y^2-12*y) = 0

3*y^2-12*y = 0

3*y*(y-4) = 0

y-4 = 0 // + 4

y = 4

3*y*(y-4) = 0

(9*y^2-24)/(3*y*(y-4)) = 0

9*y^2 = 24 // : 9

y^2 = 8/3

y^2 = 8/3 // ^ 1/2

abs(y) = (8/3)^(1/2)

y = (8/3)^(1/2) or y = -(8/3)^(1/2)

y in { (8/3)^(1/2), -(8/3)^(1/2) }

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